(3v-7)(2v^2-5v+4)=

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Solution for (3v-7)(2v^2-5v+4)= equation: 


Simplifying
(3v + -7)(2v2 + -5v + 4) = 0

Reorder the terms:
(-7 + 3v)(2v2 + -5v + 4) = 0

Reorder the terms:
(-7 + 3v)(4 + -5v + 2v2) = 0

Multiply (-7 + 3v) * (4 + -5v + 2v2)
(-7(4 + -5v + 2v2) + 3v * (4 + -5v + 2v2)) = 0
((4 * -7 + -5v * -7 + 2v2 * -7) + 3v * (4 + -5v + 2v2)) = 0
((-28 + 35v + -14v2) + 3v * (4 + -5v + 2v2)) = 0
(-28 + 35v + -14v2 + (4 * 3v + -5v * 3v + 2v2 * 3v)) = 0
(-28 + 35v + -14v2 + (12v + -15v2 + 6v3)) = 0

Reorder the terms:
(-28 + 35v + 12v + -14v2 + -15v2 + 6v3) = 0

Combine like terms: 35v + 12v = 47v
(-28 + 47v + -14v2 + -15v2 + 6v3) = 0

Combine like terms: -14v2 + -15v2 = -29v2
(-28 + 47v + -29v2 + 6v3) = 0

Solving
-28 + 47v + -29v2 + 6v3 = 0

Solving for variable 'v'.

The solution to this equation could not be determined.

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